Optimal. Leaf size=101 \[ -\frac {5 b^{5/2} x^3 \left (\frac {a}{b x^4}+1\right )^{3/4} F\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{21 \sqrt {a} \left (a+b x^4\right )^{3/4}}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3} \]
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Rubi [A] time = 0.04, antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {277, 237, 335, 275, 231} \[ -\frac {5 b^{5/2} x^3 \left (\frac {a}{b x^4}+1\right )^{3/4} F\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{21 \sqrt {a} \left (a+b x^4\right )^{3/4}}-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7} \]
Antiderivative was successfully verified.
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Rule 231
Rule 237
Rule 275
Rule 277
Rule 335
Rubi steps
\begin {align*} \int \frac {\left (a+b x^4\right )^{5/4}}{x^8} \, dx &=-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}+\frac {1}{7} (5 b) \int \frac {\sqrt [4]{a+b x^4}}{x^4} \, dx\\ &=-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}+\frac {1}{21} \left (5 b^2\right ) \int \frac {1}{\left (a+b x^4\right )^{3/4}} \, dx\\ &=-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}+\frac {\left (5 b^2 \left (1+\frac {a}{b x^4}\right )^{3/4} x^3\right ) \int \frac {1}{\left (1+\frac {a}{b x^4}\right )^{3/4} x^3} \, dx}{21 \left (a+b x^4\right )^{3/4}}\\ &=-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}-\frac {\left (5 b^2 \left (1+\frac {a}{b x^4}\right )^{3/4} x^3\right ) \operatorname {Subst}\left (\int \frac {x}{\left (1+\frac {a x^4}{b}\right )^{3/4}} \, dx,x,\frac {1}{x}\right )}{21 \left (a+b x^4\right )^{3/4}}\\ &=-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}-\frac {\left (5 b^2 \left (1+\frac {a}{b x^4}\right )^{3/4} x^3\right ) \operatorname {Subst}\left (\int \frac {1}{\left (1+\frac {a x^2}{b}\right )^{3/4}} \, dx,x,\frac {1}{x^2}\right )}{42 \left (a+b x^4\right )^{3/4}}\\ &=-\frac {5 b \sqrt [4]{a+b x^4}}{21 x^3}-\frac {\left (a+b x^4\right )^{5/4}}{7 x^7}-\frac {5 b^{5/2} \left (1+\frac {a}{b x^4}\right )^{3/4} x^3 F\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{21 \sqrt {a} \left (a+b x^4\right )^{3/4}}\\ \end {align*}
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Mathematica [C] time = 0.01, size = 52, normalized size = 0.51 \[ -\frac {a \sqrt [4]{a+b x^4} \, _2F_1\left (-\frac {7}{4},-\frac {5}{4};-\frac {3}{4};-\frac {b x^4}{a}\right )}{7 x^7 \sqrt [4]{\frac {b x^4}{a}+1}} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.03, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (b x^{4} + a\right )}^{\frac {5}{4}}}{x^{8}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{4} + a\right )}^{\frac {5}{4}}}{x^{8}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.14, size = 0, normalized size = 0.00 \[ \int \frac {\left (b \,x^{4}+a \right )^{\frac {5}{4}}}{x^{8}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{4} + a\right )}^{\frac {5}{4}}}{x^{8}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (b\,x^4+a\right )}^{5/4}}{x^8} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 3.39, size = 31, normalized size = 0.31 \[ - \frac {b^{\frac {5}{4}} {{}_{2}F_{1}\left (\begin {matrix} - \frac {5}{4}, \frac {1}{2} \\ \frac {3}{2} \end {matrix}\middle | {\frac {a e^{i \pi }}{b x^{4}}} \right )}}{2 x^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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